Answers to Selected Exercises in Chapter 6

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Section 6.2 Section 6.3 Section 6.4 Section 6.5 Section 6.6 Section 6.7 Section 6.8

Section 6.1


5. ò-13( 2x+3-x2) dx = 32/3

7. ò01( x-( 2x2-x3) ) dx = 1/12

9. ò-11( x2+1-2x2) dx = 4/3

11. ò-11( x4+1-2x2) dx = 16/15

13. 2ò01( x3-x5) dx = 1/6

15. 2ò01( 2-x2-x) dx = 7/3

17. ó
õ
-1/2

-2

( | x| -( x+1) )dx+ ó
õ
1

-1/2

( ( x+1) -| x| ) dx = 7/2

19.  ò0p/3( sin( 2x) -sin( x)) dx+òp/3p( sin( x) -sin(2x) ) dx = 5/2

21. ò0ln( 4) ( 5-ex+4e-x) dx = 10ln( 2)

23. ò0p/4( secx-tanx) dx = ln( Ö2+1) -ln( 2) /2

25. omit

27.  ò0p/6( sec2( x) -2sec( x)tan( x) ) dx+òp/6p/4( 2sec(x) tan( x) -sec2( x) ) dx = 1-2[Ö3]+2Ö2

29. ò1¥( x-2-x-3) dx = 1/2
 
 


Section 6.2

5. V = 01(3x+2)2dx = 13p

7. V = 03( x+1) dx = 15p/2

9. V = 0psin( x) dx = 2p

11. intersect at x = 0 and x = 1:    V = 01( ( [Ö(x)]) 2-( x2) 2) dx = 3p/10

13. omit: typographical error

15. V = 0p/4( 2cos2( x) -1)dx = 0p/4cos( 2x) dx = p/2

17. V = 201xÖ{1-x2}dx = 2p/3

19. revolve f( x) = Ö{R2-x2} over [ 0,R] about the y-axis;

V = 2p ó
õ
R

0

x   æ
Ö

R2-x2
dx 2pR3
3

21. Revolve f( x) = bÖ{( 1-x2/a2) } over [ -a,a] about x-axis:

V = pb2 ó
õ
a

-a

æ
ç
è
1- x2
a2
ö
÷
ø
dx 4p
3
b2a



Section 6.3

5. L = ò01Ö{1+( 32) }dx = [Ö10]

7. L = ò01Ö{1+( 3/2x1/2) 2}dx = ( 13[Ö13]-8) /27

9. change interval to [ p/6,p/2] :

       L = òp/6p/2Ö{1+( cotx) 2}dx = ln(4)

11. interval is [ 0,1] : will use identities (6.15) and (6.16)

L ó
õ
1

0

  æ
Ö

1+ æ
ç
è
1
2
x1/2- 1
2
x-1/2 ö
÷
ø
2
 
dx 4
3

13. will use identities (6.15) and (6.16):

L ó
õ
1

0

  æ
Ö

1+ æ
ç
è
e4x- 1
4
e-4x ö
÷
ø
2
 
dx 1
4
e4- 1
16
e-4- 3
16

15. will use identities (6.15) and (6.16):

L ó
õ
ln( 2) 

1

  æ
Ö

1+ æ
ç
è
e2x-e-2x
2
ö
÷
ø
2
 
dx = - 1
4
e2+ 1
4
e-2+ 15
16

17. change interval to [ 1,2] :

L ó
õ
2

1

  æ
Ö

1+( x3-1) 
dx 8
5
Ö2- 2
5

19. change interval to [ 0,p/3] :

L ó
õ
p/3

0

  æ
Ö

1+( sec4( x) -1) 
dx = Ö

21. the arclength is

L ó
õ
p/3

p/6

  æ
Ö

1+( cot( 2x) ) 2
dx = ln( 4) 

21. since f'( x) = x2, we have

L ó
õ
1

0

  æ
Ö

1+x4
dx = 1.0894294132 

23. since f'( x) = ( x+1) -1/2/2, we have

L ó
õ
1

0

  æ
Ö

1+ 1
4( x+1) 
  dx = 1.0830642795 

25. since f'( x) = ex, we have

L ó
õ
1

0

  æ
Ö

1+e2x
dx = 2.0034971116 

27. Since F'( x) = e-x^2/2, we have

L ó
õ
1

0

  æ
Ö

1+e-x^2
dx = 1.3194285585 

 



Section 6.4

 
_
x
1
A
ó
õ
b

a

x[ f( x) -g( x)] dx _
y
1
2A
ó
õ
b

a

( f(x) 2-g( x) 2) dx

5. Area is A = ò-13( 2x+3-x2) dx = 32/3:

_
x
3
32
ó
õ
3

-1

x( 2x+3-x2) dx = 1,  _
y
3
64
ó
õ
3

-1

( ( 2x+3) 2-x4)dx 17
5

7. Area is A = ò01( x-( 2x2-x3) )dx = 1/12 :

_
x
= 12 ó
õ
1

0

x( x-( 2x2-x3) ) dx 2
5
_
y
= 6 ó
õ
1

0

( x2-(2x2-x3) 2) dx 12
35

9. Area is A = ò-11( x2+1-2x2) dx = 4/3:

_
x
3
4
ó
õ
1

-1

x( x2+1-2x2) dx = 0,  _
y
3
8
ó
õ
1

-1

( ( x2+1)2-( 2x2) 2) dx 4
5

11. Area is A = ò-11( x4+1-2x2) dx = 16/15:

_
x
15
16
ó
õ
1

-1

x( x4+1-2x2) dx = 0,  _
y
15
32
ó
õ
1

-1

( ( x4+1)2-( 2x2) 2) dx 2
3

13. Area is A = 2ò01( x3-x5) dx = 1/6:

_
x
6 ó
õ
0

-1

x( x5-x3) dx+6 ó
õ
1

0

x(x3-x5) dx = 0 
_
y
3 ó
õ
0

-1

( x10-x6) dx+3 ó
õ
1

0

(x6-x10) dx = 0



15. Area is A = 2ò01( 2-x2-x) dx = 7/3:

_
x
3
7
ó
õ
1

-1

x( 2-x2-| x| )dx _
y
3
14
ó
õ
1

-1

( ( 2-x2)2-x2) dx 38
35

17. Area is A = 2ò0p/4( sec2( x) -tan2( x) ) dx = p/2:

_
x
2
p
ó
õ
p/4

-p/4

x( sec2(x) -tan2( x) ) dx = 0,  _
y
1
p
ó
õ
p/4

-p/4

( sec4( x) -tan4(x) ) dx 4
p
- 1
2

19. omit because of cosh(x):

21. Area is A = ò0Ö{p}sin( x2) dx » 0.8948

_
x
1
0.8948
ó
õ
Ö{p}

0

xsin(x2) dx » 1.1176,  _
y
1
2(0.8948) 
ó
õ
Ö{p}

0

sin2(x2) dx » 0.3743 

23. Area is upper half os unit circle of radius 1: A = p/2

_
x
2
p
ó
õ
1

-1

x   æ
Ö

1-x2
dx = 0,  _
y
1
p
ó
õ
1

-1

( 1-x2) dx 4
3p

25. Area is A = ò14( e5x-4-ex^2) dx = 627,822.3885

_
x
1
627,822.3885
ó
õ
4

1

x(e5x-4-ex^2) dx = 3.68, 
_
y
1
2( 627,822.3885) 
ó
õ
4

1

(e10x-8-e2x^2) dx = 2,293,694.5107

 



Section 6.5

5.
d
dx
tan-1( 3x) =  3
1+9x2

7.

d
dx
tan-1( ex) =  ex
1+e2x

9.

d
dx
tan-1( Öx) =  1
2Öx( x+1) 

11.

d
dx
Öxtan-1( Öx) =  1
2Öx
tan-1( Öx) + 1
2( x+1) 

13.

d
dx
sin( 2tan-1( x) ) =   2 cos( 2tan-1( x) )
1+x2
= 2 x2-1
( 1+x2) 2

15.

ó
õ
dx
x
2+16
1
4
tan-1 æ
ç
è
x
4
ö
÷
ø
+C

17.

ó
õ
exdx
e
2x+1
= tan-1( ex) +C

19.

ó
õ
1

0

xdx
x
4+3
3
36

21.

ó
õ
xtan-1( x) dx 1
2
x2tan-1( x)- 1
2
x+ 1
2
tan-1( x) +C

23.

cos( tan-1( x) ) =  1
  æ
Ö

1+x2

25.

cos( 2sin-1( x) ) = 1-2x2

27.

sin( tan-1( x2) ) =  x2
  æ
Ö

1+x4



Section 6.6


5.

d
dx
sin-1( 3x) =  3
  æ
Ö

1-9x2

7.

d
dx
sin-1( ex) =  ex
  æ
Ö

1-e2x

9.

d
dx
sin-1( Öx) =  1
2Öx   ___
Ö1-x

11.

d
dx
( cos-1( x) +sin-1( x)) = 0 

13.

d
dx
sin( 2sin-1( x) ) =  2 cos( 2sin-1x)
  æ
Ö

1-x2
=  2 1-2x2
  æ
Ö

1-x2

15.

ó
õ
dx
  æ
Ö

5-x2
= sin-1 æ
ç
è
xÖ5
5
ö
÷
ø

17. omit: have not covered these functions yet

19.

ó
õ
( 2x+1) dx
  æ
Ö

1-( x2+x) 2
d
dx
sin-1( x2+x) +C

21. multiply top and bottom by ex:

ó
õ
dx
  æ
Ö

e-2x-1
ó
õ
ex  dx
  æ
Ö

1-e2x
= sin-1( ex) +C

23. consider that x = ( Öx) 2 if x > 0. Thus,

ó
õ
dx
Öx   æ
Ö

1-( Öx) 2
= 2sin-1( Öx) +C

25. (this one is not easy!)

ó
õ
xsin-1( x) dx 1
2
x2sin-1( x) - 1
4
sin-1( x) + 1
4
x   æ
Ö

1-x2
+C

27.

sin( cos-1( 2x) ) =    æ
Ö

1-4x2

29.

tan( sin-1( x) ) =  x
  æ
Ö

1-x2

31.

cos( 2sin-1( x) ) = 1-2x2

 
 



Section 6.7


5.

ó
õ
1.5

0

x
9-x2
dx = - 1
2
ln3+ln2

7.

ó
õ
2Ö3

0

x2
  æ
Ö

16-x2
dx =  -2Ö3+ 8
3
p

9.

ó
õ
Ö3

0

dx
x   æ
Ö

x2+3
¥

11.

ó
õ
1

-1

  æ
Ö

1-x2
dx p
2

13.

ó
õ
[Ö15]

0

dx
( x2+5) 3/2
Ö3
10

15.

ó
õ
dx
x2   æ
Ö

4+x2
=  - 1
4x
  æ
Ö

4+x2
+C

17.

ó
õ
dx
( 25-x2) 3/2
1
25
x
  æ
Ö

25-x2
+C

19.

ó
õ
1

0

Öx
  æ
Ö

1-x2
dx ó
õ
p/2

0

  æ
Ö

sin( q
dq = 1.19814

21.

ó
õ
3

0

  æ
Ö

16-x2
9-x2
dx ó
õ
p/2

0

  æ
Ö

16-9sin2( q
dq = 5. 27388 8432

23.

ó
õ
3

0

dx
  æ
Ö

x( 9-x2
ó
õ
p/2

0

dq
  æ
Ö

3sin( q
= 1. 51384 56348




 

Section 6.8

5. 2xsinh( x2)

7. 3x2cosh( x3)

9. tanh( x)

11.  exsech( x) -extanh( x) sech2( x)

13. 2cosh( x) sinh( x)

15. 6x2sinh( x3) cosh( x3)

17. cosh( px) /p+C

19. òx2cosh( x) dxx2sinhx-2xcoshx+2sinhx+C

21.

ó
õ
sinh2( x)
cosh3( x
dx =   - sinhx
2cosh2x
+tan-1( ex) +C

23.

ó
õ
dx
tanh( x) +sech( x
ó
õ
cosh( x) dx
sinh( x) +1
= ln( sinhx+1) +C

25.

ó
õ
1
cosh( x
dx = 2tan-1( ex) +C

27. 5.1983485413

29.

ó
õ
3

2

sin æ
ç
ç
ç
ç
è
1
  æ
Ö

x2-4
ö
÷
÷
÷
÷
ø
dx =0.62724 57965 1