Answers to Selected Exercises in Chapter 6
Click Links in table below to advance to solutions for that section.
Section 6.1
5. ò-13(
2x+3-x2) dx = 32/3
7. ò01( x-(
2x2-x3) ) dx = 1/12
9. ò-11( x2+1-2x2)
dx
= 4/3
11. ò-11( x4+1-2x2)
dx
= 16/15
13. 2ò01( x3-x5)
dx
= 1/6
15. 2ò01( 2-x2-x)
dx
= 7/3
| 17. |
ó
õ |
-1/2
-2 |
( | x| -( x+1) )dx+ |
ó
õ |
1
-1/2 |
( ( x+1) -| x| ) dx = 7/2 |
|
19. ò0p/3(
sin( 2x) -sin( x)) dx+òp/3p(
sin( x) -sin(2x) ) dx = 5/2
21. ò0ln( 4) (
5-ex+4e-x) dx = 10ln(
2)
23. ò0p/4(
secx-tanx) dx = ln( Ö2+1)
-ln( 2) /2
25. omit
27. ò0p/6(
sec2( x) -2sec( x)tan( x) ) dx+òp/6p/4(
2sec(x) tan( x) -sec2( x) ) dx =
1-2[Ö3]+2Ö2
29. ò1¥(
x-2-x-3)
dx
= 1/2
Section 6.2
5. V = pò01(3x+2)2dx
= 13p
7. V = pò03(
x+1)
dx = 15p/2
9. V = pò0psin(
x)
dx = 2p
11. intersect at x = 0 and x = 1:
V
= pò01( ( [Ö(x)])
2-( x2)
2) dx = 3p/10
13. omit: typographical error
15. V = pò0p/4(
2cos2( x) -1)dx = pò0p/4cos(
2x) dx = p/2
17. V = 2pò01xÖ{1-x2}dx
= 2p/3
19. revolve f( x) = Ö{R2-x2}
over [ 0,R] about the y-axis;
| V = 2p |
ó
õ |
R
0 |
x |
æ
Ö |
|
R2-x2 |
dx = |
2pR3
3 |
|
|
21. Revolve f( x) = bÖ{(
1-x2/a2) } over [ -a,a]
about x-axis:
| V = pb2 |
ó
õ |
a
-a |
|
æ
ç
è |
1- |
x2
a2 |
|
ö
÷
ø |
dx = |
4p
3 |
b2a |
|
Section 6.3
5. L = ò01Ö{1+(
32) }dx = [Ö10]
7. L = ò01Ö{1+(
3/2x1/2)
2}dx = ( 13[Ö13]-8) /27
9. change interval to [ p/6,p/2]
:
L = òp/6p/2Ö{1+(
cotx) 2}dx = ln(4)
11. interval is [ 0,1] : will use identities (6.15) and (6.16)
| L = |
ó
õ |
1
0 |
|
æ
Ö |
|
| 1+ |
æ
ç
è |
|
1
2 |
x1/2- |
1
2 |
x-1/2 |
ö
÷
ø |
2
|
|
|
dx = |
4
3 |
|
|
13. will use identities (6.15) and (6.16):
| L = |
ó
õ |
1
0 |
|
æ
Ö |
|
| 1+ |
æ
ç
è |
e4x- |
1
4 |
e-4x |
ö
÷
ø |
2
|
|
|
dx = |
1
4 |
e4- |
1
16 |
e-4- |
3
16 |
|
|
15. will use identities (6.15) and (6.16):
| L = |
ó
õ |
ln( 2)
1 |
|
æ
Ö |
|
| 1+ |
æ
ç
è |
|
e2x-e-2x
2 |
|
ö
÷
ø |
2
|
|
|
dx = - |
1
4 |
e2+ |
1
4 |
e-2+ |
15
16 |
|
|
17. change interval to [ 1,2] :
| L = |
ó
õ |
2
1 |
|
æ
Ö |
|
1+( x3-1) |
dx = |
8
5 |
Ö2- |
2
5 |
|
|
19. change interval to [ 0,p/3] :
| L = |
ó
õ |
p/3
0 |
|
æ
Ö |
|
1+( sec4( x) -1) |
dx = Ö3 |
|
21. the arclength is
| L = |
ó
õ |
p/3
p/6 |
|
æ
Ö |
|
1+( cot( 2x) ) 2 |
dx = ln( 4) |
|
21. since f'( x) = x2,
we have
| L = |
ó
õ |
1
0 |
|
æ
Ö |
|
1+x4 |
dx = 1.0894294132 |
|
23. since f'( x) = ( x+1)
-1/2/2,
we have
| L = |
ó
õ |
1
0 |
|
æ
Ö |
|
|
dx = 1.0830642795 |
|
25. since f'( x) = ex,
we have
| L = |
ó
õ |
1
0 |
|
æ
Ö |
|
1+e2x |
dx = 2.0034971116 |
|
27. Since F'( x) = e-x^2/2,
we have
| L = |
ó
õ |
1
0 |
|
æ
Ö |
|
1+e-x^2 |
dx = 1.3194285585 |
|
Section 6.4
|
_
x |
= |
1
A |
|
ó
õ |
b
a |
x[ f( x) -g( x)] dx, |
_
y |
= |
1
2A |
|
ó
õ |
b
a |
( f(x) 2-g( x) 2)
dx |
|
5. Area is A = ò-13(
2x+3-x2) dx = 32/3:
|
_
x |
= |
3
32 |
|
ó
õ |
3
-1 |
x( 2x+3-x2) dx = 1, |
_
y |
= |
3
64 |
|
ó
õ |
3
-1 |
( ( 2x+3) 2-x4)dx
= |
17
5 |
|
|
7. Area is A = ò01(
x-(
2x2-x3) )dx = 1/12 :
|
_
x |
= 12 |
ó
õ |
1
0 |
x( x-( 2x2-x3)
) dx = |
2
5 |
, |
_
y |
= 6 |
ó
õ |
1
0 |
( x2-(2x2-x3)
2)
dx = |
12
35 |
|
|
9. Area is A = ò-11(
x2+1-2x2)
dx = 4/3:
|
_
x |
= |
3
4 |
|
ó
õ |
1
-1 |
x( x2+1-2x2) dx
= 0, |
_
y |
= |
3
8 |
|
ó
õ |
1
-1 |
( ( x2+1)2-( 2x2)
2)
dx = |
4
5 |
|
|
11. Area is A = ò-11(
x4+1-2x2)
dx = 16/15:
|
_
x |
= |
15
16 |
|
ó
õ |
1
-1 |
x( x4+1-2x2) dx
= 0, |
_
y |
= |
15
32 |
|
ó
õ |
1
-1 |
( ( x4+1)2-( 2x2)
2)
dx = |
2
3 |
|
|
13. Area is A = 2ò01(
x3-x5)
dx = 1/6:
|
|
|
|
| 6 |
ó
õ |
0
-1 |
x( x5-x3) dx+6 |
ó
õ |
1
0 |
x(x3-x5) dx
= 0 |
|
|
|
|
| 3 |
ó
õ |
0
-1 |
( x10-x6) dx+3 |
ó
õ |
1
0 |
(x6-x10) dx = 0 |
|
|
|
|

15. Area is A = 2ò01(
2-x2-x) dx = 7/3:
|
_
x |
= |
3
7 |
|
ó
õ |
1
-1 |
x( 2-x2-| x| )dx, |
_
y |
= |
3
14 |
|
ó
õ |
1
-1 |
( ( 2-x2)2-x2)
dx
= |
38
35 |
|
|
17. Area is A = 2ò0p/4(
sec2( x) -tan2( x) ) dx = p/2:
|
_
x |
= |
2
p |
|
ó
õ |
p/4
-p/4 |
x( sec2(x) -tan2( x)
) dx = 0, |
_
y |
= |
1
p |
|
ó
õ |
p/4
-p/4 |
( sec4( x) -tan4(x) ) dx
= |
4
p |
- |
1
2 |
|
|
19. omit because of cosh(x):
21. Area is A = ò0Ö{p}sin(
x2)
dx » 0.8948
|
_
x |
= |
1
0.8948 |
|
ó
õ |
Ö{p}
0 |
xsin(x2) dx »
1.1176, |
_
y |
= |
1
2(0.8948) |
|
ó
õ |
Ö{p}
0 |
sin2(x2) dx »
0.3743 |
|
23. Area is upper half os unit circle of radius 1: A = p/2
|
_
x |
= |
2
p |
|
ó
õ |
1
-1 |
x |
æ
Ö |
|
1-x2 |
dx = 0, |
_
y |
= |
1
p |
|
ó
õ |
1
-1 |
( 1-x2) dx = |
4
3p |
|
|
25. Area is A = ò14(
e5x-4-ex^2)
dx = 627,822.3885
|
|
|
|
|
1
627,822.3885 |
|
ó
õ |
4
1 |
x(e5x-4-ex^2)
dx
= 3.68, |
|
|
|
|
|
1
2( 627,822.3885) |
|
ó
õ |
4
1 |
(e10x-8-e2x^2)
dx
= 2,293,694.5107 |
|
|
|
|
Section 6.5
5.
|
d
dx |
tan-1( 3x) = |
3
1+9x2 |
|
|
7.
|
d
dx |
tan-1( ex) = |
ex
1+e2x |
|
|
9.
|
d
dx |
tan-1( Öx)
= |
1
2Öx( x+1) |
|
|
11.
|
d
dx |
Öxtan-1(
Öx)
= |
1
2Öx |
tan-1( Öx)
+ |
1
2( x+1) |
|
|
13.
|
d
dx |
sin( 2tan-1( x) ) =
2 |
cos( 2tan-1( x) )
1+x2 |
= 2 |
x2-1
( 1+x2) 2 |
|
|
15.
|
ó
õ |
|
dx
x2+16 |
= |
1
4 |
tan-1 |
æ
ç
è |
|
x
4 |
|
ö
÷
ø |
+C |
|
17.
|
ó
õ |
|
exdx
e2x+1 |
= tan-1( ex) +C |
|
19.
|
ó
õ |
1
0 |
|
xdx
x4+3 |
= |
pÖ3
36 |
|
|
21.
|
ó
õ |
xtan-1( x) dx = |
1
2 |
x2tan-1( x)- |
1
2 |
x+ |
1
2 |
tan-1( x) +C |
|
23.
25.
| cos( 2sin-1( x) ) = 1-2x2 |
|
27.
Section 6.6
5.
7.
9.
11.
|
d
dx |
( cos-1( x) +sin-1(
x))
= 0 |
|
13.
|
d
dx |
sin( 2sin-1( x) ) = 2 |
cos( 2sin-1x)
|
= 2 |
1-2x2
|
|
|
15.
|
ó
õ |
|
dx
|
= sin-1 |
æ
ç
è |
|
xÖ5
5 |
|
ö
÷
ø |
|
|
17. omit: have not covered these functions yet
19.
|
ó
õ |
|
( 2x+1) dx
|
= |
d
dx |
sin-1( x2+x)
+C |
|
21. multiply top and bottom by ex:
|
ó
õ |
|
dx
|
= |
ó
õ |
|
ex dx
|
= sin-1( ex) +C |
|
23. consider that x = ( Öx)
2
if x > 0. Thus,
25. (this one is not easy!)
|
ó
õ |
xsin-1( x) dx = |
1
2 |
x2sin-1( x)
- |
1
4 |
sin-1( x) + |
1
4 |
x |
æ
Ö |
|
1-x2 |
+C |
|
27.
| sin( cos-1( 2x) ) = |
æ
Ö |
|
1-4x2 |
|
|
29.
31.
| cos( 2sin-1( x) ) = 1-2x2 |
|
Section 6.7
5.
|
ó
õ |
1.5
0 |
|
x
9-x2 |
dx = - |
1
2 |
ln3+ln2 |
|
7.
|
ó
õ |
2Ö3
0 |
|
x2
|
dx = -2Ö3+ |
8
3 |
p |
|
9.
11.
|
ó
õ |
1
-1 |
|
æ
Ö |
|
1-x2 |
dx = |
p
2 |
|
|
13.
|
ó
õ |
[Ö15]
0 |
|
dx
( x2+5) 3/2 |
= |
Ö3
10 |
|
|
15.
|
ó
õ |
|
dx
|
= - |
1
4x |
|
æ
Ö |
|
4+x2 |
+C |
|
17.
|
ó
õ |
|
dx
( 25-x2) 3/2 |
= |
1
25 |
|
x
|
+C |
|
19.
|
ó
õ |
1
0 |
|
Öx
|
dx = |
ó
õ |
p/2
0 |
|
æ
Ö |
|
sin( q) |
dq = 1.19814 |
|
21.
|
ó
õ |
3
0 |
|
æ
Ö |
|
|
dx = |
ó
õ |
p/2
0 |
|
æ
Ö |
|
16-9sin2( q) |
dq = 5. 27388
8432 |
|
23.
|
ó
õ |
3
0 |
|
dx
|
= |
ó
õ |
p/2
0 |
|
dq
|
= 1. 51384 56348 |
|
Section 6.8
5. 2xsinh( x2)
7. 3x2cosh( x3)
9. tanh( x)
11. exsech( x) -extanh(
x)
sech2( x)
13. 2cosh( x) sinh( x)
15. 6x2sinh( x3) cosh( x3)
17. cosh( px) /p+C
19. òx2cosh( x)
dx
= x2sinhx-2xcoshx+2sinhx+C
21.
|
ó
õ |
|
sinh2( x)
cosh3( x) |
dx = - |
sinhx
2cosh2x |
+tan-1( ex) +C |
|
23.
|
ó
õ |
|
dx
tanh( x) +sech( x) |
= |
ó
õ |
|
cosh( x) dx
sinh( x) +1 |
= ln( sinhx+1) +C |
|
25.
|
ó
õ |
|
1
cosh( x) |
dx = 2tan-1( ex)
+C |
|
27. 5.1983485413
29.
|
ó
õ |
3
2 |
sin |
æ
ç
ç
ç
ç
è |
|
1
|
|
ö
÷
÷
÷
÷
ø |
dx =0.62724 57965 1 |
|