A Special case of Torricelli’s Law
Using Separation of variables and Graphical analysis to solve a Differential
Equation
By
Justin Christian
And
David McAllister
Use of separation of variables and graphical analysis
in solving a special case of Torricelli’s Law
In this problem we are presented with a situation where we have a can full of water with a small hole in the bottom. We need to know how long it will take a certain amount of water to drain out of the hole. By use of a special case of Torricelli’s Law, we observe that the change in the height of water in the can is proportional to the square root of the height, that is (dy/dx) = k (y)^1/2. By use of this law, we can determine the amount of time required for the water to drain.
Given the following set of data, we will apply Torricelli’s law and use the separation of variable technique to solve this differential equation.
Original Data
| t (minutes) | 0 | 0.5 | 1 | 1.5 | 2 |
| Y (inches) | 3.063 | 2.5 | 2.125 | 1.75 | 1.375 |
Below is a graph of the original data points:
First, we need to solve the differential equation:
(1) (dy/dt) = k (y)^1/2
We need to separate the variables to get:
(2) 1/(y)^1/2 (dy) = k (dt)
We then integrate to get:
(3) y^1/2
--------
= kt+C
1/2
This is simplified to get:
(4) 2 (Y)^1/2 = kt + C
We now need to find a linear relationship between the variables in order to produce a graph of the data.
If we let Y = 2(y)^1/2 and let T = (t), we can rewrite
the equation as:
(5) Y = kT + C
We can now rewrite the data as:
Transformed Data
| T (minutes) | 0 | 0.5 | 1 | 1.5 | 2 |
| Y (inches) | 3.5 | 3.162 | 2.915 | 2.646 | 2.345 |
We now are able to plot these points and using a HP Calculator, we can
build a Linear Regression Graph, which will give us the values
for C and for k.
We use the Slope of this line to find k and we use the Y-Intercept as the value of C.
k = -.5652
C = 3.4788
With this information in hand, we can now rewrite our equation as:
(6) Y = -. 5652 T + 3.4788
By substituting Y with 2*(Y)^1/2, our equation now reads
(7) 2* (Y)^1/2 = -. 5652 T + 3.4788
In order to determine the time (T) where all of the liquid has
drained, we can set (Y) = 0 and we get:
(8) 2 * (0)^1/2 = -. 5652 T + 3.4788
By solving for (T), we find that (T) = 6.155 sec.
This is the amount of time it takes the liquid to drain from the can.
Now let us look for the best fitting curve. We start with the equation:
(9) 2* (Y)^1/2 = -. 5652 T + 3.4788
Let’s solve for Y. we get:
(10) Y = (1.7394 - .2825 T)^2.
Below is the graph of this curve:
By taking our original data, we transformed the data and found a linear relationship
between time T and the change in height Y. We were then able to compute our constant
of proportionality k and determine the constant C. Using this equation, we were able to
determine the amount of time T that it took for the can of soup to drain completely. Then
we took the information from the linear graph and constructed an estimated function
curve that fit the original data points. This estimated function models
the original data.