1] A 0.150 kg object tied to a string is
whirled
in a horizontal circle at a constant angular speed
of 3.50 revolutions/sec.
The tension in the string is 75.0 N. What is the length of the string?
ANSWER: 1.03 m
2] A wheel of diameter 0.80 m is initially
at
rest. It is then rotated with a constant angular
acceleration of 5.0 rad/s2
for exactly 10 revolutions of the wheel. Determine both the angular
speed of the wheel and the
tangential speed for a point on the edge of the wheel at the end
of the 10 revolutions.
ANSWER: 25 rad/s , 10 m/s
1] A 150 gm object tied to a string is
whirled
in a horizontal circle such that the tension in the
string is 75.0 N when the
angular speed is 3.50 revolutions/sec. How many meters, s, does
the object travel in 5.00
seconds? [ NOTE
s is the circumferential distance traveled around
the circle.]
3] A uniform beam 3.00 meters long has a
weight
of 245 N. It is supported on its left end by a cable.
A 500 N weight is located
on the beam a distance of 1.00 meter from the left end. You supply a
force to the right end of
the beam so that the beam is in equilibrium in the horizontal position
(see
sketch). What are the
tension
in the cable, T, and the upward force, F, you must apply to the beam?
{HINT : Apply the
equilibrium
condition for two different axis’ of rotation !!}

3] A solid wood sphere floats in alcohol (r
= 0.806 x 103 kg/m3) such that exactly one half
of
the
sphere is submerged in the
fluid.
A} Find the density of the wood.
ANSWER: 403 kg/m3
B} Give the name and define the principle involved in the solution of this problem.
ANSWER: Archimedes principle
4] A concrete canoe must be constructed
such that
most of its volume is air to insure that it will float in
water. Assume such a canoe can be
approximated as a
uniform solid cube with sides 2.0 meters in length.
When placed in water, the cube floats upright
with its bottom 1.5 meters below the water surface.
A)
Find the
average density for the concrete
canoe.
ANS: 0.75 gm/cm^3
B)
Find the
absolute pressure at the bottom
of the canoe.
ANS: 1.16 x 10^5 Pa
3] A
uniform beam 4.00 meters long has a
weight of 350 N. It
is supported at a point 1.00 meter from
the right
end by a fulcrum. A 500 N
weight is located on the beam a distance of 1.00 meter from the left
end. You supply a force
directed at the
right end of the beam so that the beam is in equilibrium in the
horizontal
position (see sketch).
Determine BOTH the
force exerted by you on the right end AND the force exerted on the beam
by the
fulcrum.

ANS: F = 1560
N Fulcrum = 2200 N
M ultiple
Choice